ARM-Linux开机自启动设置-ok6410开发板

Problem Description The digital root of a positive integer is found by summing the digits of the integer. If the resulting value is a single digit then that digit is the digital root. If the resulting value contains two or more digits, those digits are summed and the process is repeated. This is continued as long as necessary to obtain a single digit.

For example, consider the positive integer 24. Adding the 2 and the 4 yields a value of 6. Since 6 is a single digit, 6 is the digital root of 24. Now consider the positive integer 39. Adding the 3 and the 9 yields 12. Since 12 is not a single digit, the process must be repeated. Adding the 1 and the 2 yeilds 3, a single digit and also the digital root of 39.

The Eddy‘s easy problem is that : give you the n,want you to find the n^n‘s digital Roots.
 
#include <iostream> #include <stdio.h> using namespace std; int main() { int n,i,s; while(scanf("%d",&n)&&n) { s = 1; for(i = 1;i<=n;i++){ s=s*n%9; } if(s==0) printf("9\n"); else printf("%d\n",s); } return 0; }

太坑了……

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